Optimal. Leaf size=145 \[ -\frac{5 c^{3/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right ),\frac{1}{2}\right )}{6 b^{9/4} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}+\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}} \]
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Rubi [A] time = 0.184625, antiderivative size = 145, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {2023, 2025, 2032, 329, 220} \[ -\frac{5 c^{3/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{6 b^{9/4} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}+\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}} \]
Antiderivative was successfully verified.
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Rule 2023
Rule 2025
Rule 2032
Rule 329
Rule 220
Rubi steps
\begin{align*} \int \frac{\sqrt{x}}{\left (b x^2+c x^4\right )^{3/2}} \, dx &=\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}}+\frac{5 \int \frac{1}{x^{3/2} \sqrt{b x^2+c x^4}} \, dx}{2 b}\\ &=\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}-\frac{(5 c) \int \frac{\sqrt{x}}{\sqrt{b x^2+c x^4}} \, dx}{6 b^2}\\ &=\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}-\frac{\left (5 c x \sqrt{b+c x^2}\right ) \int \frac{1}{\sqrt{x} \sqrt{b+c x^2}} \, dx}{6 b^2 \sqrt{b x^2+c x^4}}\\ &=\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}-\frac{\left (5 c x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{3 b^2 \sqrt{b x^2+c x^4}}\\ &=\frac{1}{b \sqrt{x} \sqrt{b x^2+c x^4}}-\frac{5 \sqrt{b x^2+c x^4}}{3 b^2 x^{5/2}}-\frac{5 c^{3/4} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{6 b^{9/4} \sqrt{b x^2+c x^4}}\\ \end{align*}
Mathematica [C] time = 0.0194315, size = 60, normalized size = 0.41 \[ -\frac{2 \sqrt{\frac{c x^2}{b}+1} \, _2F_1\left (-\frac{3}{4},\frac{3}{2};\frac{1}{4};-\frac{c x^2}{b}\right )}{3 b \sqrt{x} \sqrt{x^2 \left (b+c x^2\right )}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.217, size = 127, normalized size = 0.9 \begin{align*} -{\frac{c{x}^{2}+b}{6\,{b}^{2}}{x}^{{\frac{3}{2}}} \left ( 5\,\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) \sqrt{-bc}x+10\,c{x}^{2}+4\,b \right ) \left ( c{x}^{4}+b{x}^{2} \right ) ^{-{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{x}}{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{c x^{4} + b x^{2}} \sqrt{x}}{c^{2} x^{8} + 2 \, b c x^{6} + b^{2} x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{x}}{\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{x}}{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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